1. 简谈密码学中常用的模运算和欧几里得算法_密码学中mod运算162 = 1 x 94 + 68 gcd(94, 68) 94 = 1 x 68 + 26 gcd(68, 26) 68 = 2 x 26 + 16 gcd(26, 16) 26 = 1 x 16 + 10 gcd(16, 10) 16 = 1 x 10 + 6 gcd(10, 6) 10 = 1 x 6 + 4 gcd(6, ...
2. 系数在Zp的多项式运算if B = 0 return A = gcd(a, b) 3. R = A mod B 4. A = B 5. B = R 6. goto 2 範例:GCD(1970,1066) 1970 = 1 x 1066 + 904 gcd(1066, 904) 1066 = 1 x 904 + 162 gcd(904, 162) 904 = 5 x...
3. 用于加密和解密的数学函数_函数与密码_ 星云 的博客162)=904-162*5=94 gcd(162,94)=162-94*1=68 gcd(94,68)=94-68*1=26 gcd(68,26)=68-26*2=16 gcd(26,16)=26-16*1=10 gcd(16,10)=16-10*1=6 gcd(10,6)=10-6*1=4 gcd(6,4)=6-4*1=2 gcd(4,2)...
4. 身高162体重127斤体重多少才正常-真实医生回答我24,女,身高162,体重127斤,请问体重多少才正常(女,24) 分析及建议: 这个身高在50-64公斤应该算是比较合适的体重,还是建议多运动,控制饮食的方法。不能只靠节食减肥。 患者 我24,女,身高162,体重127斤,请问体重多少才正常(女,...
5. CodeForces 1285 C Fadi and LCM (GCD)_51CTO博客_xn--c-r4tCodeForces 1285 C Fadi and LCM (GCD) Description: Today, Osama gave Fadi an integer , and Fadi was wondering about the minimum possible value of such that equals . Both and
6. AtCoder Beginner Contest 162 E - Sum of gcd of Tuples一个长度为nn的序列{A1,A2,...,An}{A1,A2,...,An}, 其中每一位AiAi取值为[1,k][1,k]. 共有knkn种序列, 求所有序列的gcd(A1,A2,...,An)gcd(A1,A2,...,An)的和.
VNDS-2743